0=8x^2+3x

Solution for 0=8x^2+3x equation:

0=8x^2+3x

We move all terms to the left:

0-(8x^2+3x)=0

We add all the numbers together, and all the variables

-(8x^2+3x)=0

We get rid of parentheses

-8x^2-3x=0

a = -8; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-8)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-8}=\frac{0}{-16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-8}=\frac{6}{-16}
=-3/8
$